X^2+30x=4000

Solution for X^2+30x=4000 equation:

X^2+30X=4000

We move all terms to the left:

X^2+30X-(4000)=0

a = 1; b = 30; c = -4000;
Δ = b2-4ac
Δ = 302-4·1·(-4000)
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16900}=130$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-130}{2*1}=\frac{-160}{2}
=-80
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+130}{2*1}=\frac{100}{2}
=50
$